Tangential Acceleration of uniform motion

AI Thread Summary
In uniform circular motion, the tangential acceleration is zero because the speed remains constant, meaning there is no change in velocity over time (dv/dt = 0). The discussion highlights confusion between tangential and radial acceleration, clarifying that the formula V^2/r applies to centripetal (radial) acceleration, not tangential. For non-uniform circular motion, tangential acceleration can exist and is determined by the angular acceleration multiplied by the radius (At = |angular acceleration| x r). The key takeaway is that in uniform circular motion, tangential acceleration does not apply. Understanding these distinctions is crucial for accurately applying the relevant formulas.
student 1
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How do you find the Magnitude of tangential acceleration if you have uniform circular motion? I know the formula for Tangential Acceleration; however I have no clue how to apply it to determine the Magnitude?
 
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Its just the magnitude of the vector. It should just be V^2/r.
 
student 1 said:
How do you find the Magnitude of tangential acceleration if you have uniform circular motion? I know the formula for Tangential Acceleration; however I have no clue how to apply it to determine the Magnitude?

The formula in the previous post is incorrect (that's the magnitude of the *radial* component of the acceleration). What formula are you using for tangential acc?
 
student 1 said:
How do you find the Magnitude of tangential acceleration if you have uniform circular motion? I know the formula for Tangential Acceleration; however I have no clue how to apply it to determine the Magnitude?
Do you mean centripetal acceleration? If something is performing uniform circular motion, its tangential acceleration is zero. Or do you mean non-uniform circular motion, which will have a tangential component of acceleration?
 
No, I mean tangential acceleration. That's probably the answer I'm looking for I just have to know how to express that the acceleration would be zero if it was uniform circular motion using words and one equation.
 
Im suppose to use At=[dv/dt].
 
student 1 said:
Im suppose to use At=[dv/dt].
OK, where v is the speed, not the velocity vector. For uniform circular motion, dv/dt = 0.
 
Tangental acceleration can still exist on a object traveling in a circular path. The centripetal force just needs to change with respect to speed2, so it always equals m |v|2 / r.

The magnitude of tangental acceleration would be the magnitude of angular acceleration times r = |angular acceleration| x r.
 
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