Tangential and radial coordinate problem. Confused about the FBD.

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving tangential and radial coordinates in a physics context, specifically focusing on the interpretation of a free body diagram (FBD) related to forces acting on a particle connected to a rod. Participants are exploring the relationships between different directional vectors in polar coordinates.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are attempting to clarify the direction of force vectors in relation to tangential and radial components. There is a discussion about the definitions of tangential vectors and their relationship to the motion of the particle versus the rod.

Discussion Status

The discussion is ongoing, with participants providing insights into the definitions of unit vectors in polar coordinates and their implications for the problem. Some guidance has been offered regarding the nature of forces acting on the particle and the distinction between different tangential directions.

Contextual Notes

There appears to be some confusion regarding the definitions of tangential and radial directions, as well as the specific setup of the problem as illustrated in the provided free body diagram. Participants are questioning assumptions about the forces involved and their directions.

theBEAST
Messages
361
Reaction score
0

Homework Statement


Here is a picture of the problem with the free body diagram:
http://dl.dropbox.com/u/64325990/HW%20Pictures/problem101.PNG

I am confused about why the free body diagram has the force vector in the direction of the aθ. When I did it I thought the force that the rod would exert on the particle would be in the tangential direction? In other words in the direction of at.
 
Last edited by a moderator:
Physics news on Phys.org
I don't see a_t in your pic.

But anyway, I am pretty sure that the tangential direction is the theta direction as well.
So a_theta = a_t

In polar coordinates the radial direction is out from the origin, and the theta direction is perpendicular to that, which would be the tangential direction.
 
spacelike said:
I don't see a_t in your pic.

But anyway, I am pretty sure that the tangential direction is the theta direction as well.
So a_theta = a_t

In polar coordinates the radial direction is out from the origin, and the theta direction is perpendicular to that, which would be the tangential direction.

No the unit vector in the tangential direction (u_t) is perpendicular to the normal direction. a_theta != a_t..

I edited the picture slightly to show the direction of a_t which is in the direction of it's unit vector u_t.
 
i'll just add this to what spacelike :smile: says …

in polar coordinates, the actual coordinates are r,θ,

and so the unit vectors for increasing r (with fixed θ), and for increasing θ (with fixed r) are called er and eθ, respectively

(or \boldsymbol{\hat{r}} and \boldsymbol{\hat{θ}})

and their velocity or acceleration components therefore have the same subscripts

(and of course, t isn't a coordinate :wink:)
 
I think I understand your confusion. There are two tangential vectors you could define. One would be the vector that is tangential to the motion of the particle and the other is tangential to any point on the rod which is rotating (but at a constant distance from the origin). The second one must be in the theta direction which is perp. to the rod. The force from the rod MUST be that force which is normal to the surface of the rod. Unless there are strange things going on, the only interaction between the rod and particle must be normal to the rod. The force that you are thinking about that would be in the u_t direction is the net force on the particle. If that were asked, you would be correct.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
24
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K