Tank Change in Flow Process Modeling

PaxFinnica96
Messages
14
Reaction score
0
Hi All,
I'm really struggling with the below question - I'm not sure if I've taken the correct approach to determining the model as there may be an easier way to do this?

Any help in much appreciated, please let me know if I have submitted this template correctly as this if my first time!
Cheers

1. Homework Statement


a. FIGURE 2 shows two cylindrical tanks interconnected with a pipe which has a valve that creates a constant resistance to flow of Rf when fully open. The height of liquid (of density ρ) in the first tank is hin and the second tank hout. The cross-sectional area of the first tank is Ain m2 and the second tank Aout m2.
upload_2019-2-21_8-34-56.png


Produce a mathematical model of the process to determine the change in height of fluid in the second tank when the valve is open.

b. Determine the time constant for the system.


Homework Equations



The flow rate of liquid through the valve is given by:[/B]

Q = 1/Rf (Pin - Pout)

Where; Q = flow rate in m^3 s^-1

Pin = pressure due to height of liquid in first tank (Pa)

Pout = pressure due to height of liquid in second tank (Pa)

The Attempt at a Solution


a[/B]
upload_2019-2-21_8-36-47.png
upload_2019-2-21_8-37-8.png

b
upload_2019-2-21_8-37-52.png

Giving a time constant of 63.2% for the system.
 

Attachments

  • upload_2019-2-21_8-34-56.png
    upload_2019-2-21_8-34-56.png
    1.5 KB · Views: 613
  • upload_2019-2-21_8-36-47.png
    upload_2019-2-21_8-36-47.png
    27.3 KB · Views: 547
  • upload_2019-2-21_8-37-8.png
    upload_2019-2-21_8-37-8.png
    19.7 KB · Views: 596
  • upload_2019-2-21_8-37-52.png
    upload_2019-2-21_8-37-52.png
    9.3 KB · Views: 592
on Phys.org
You don't need the final differential equation to determine ##h_{out}##. You have two algebraic equations in two unknowns:
$$A_{in}h_{in}+A_{out}h_{out}=A_{in}h_{in,0}+A_{out}h_{out,0}$$
and $$h_{in}-h_{out}=(h_{in,0}-h_{out,0})e^{-t/\tau}$$
 
So instead of differentiating at the end I should just leave the equations as they are like below?

222195-b54ffaec0afbba6d5453a104228544fb.jpg
 

Attachments

  • 1234.jpg
    1234.jpg
    33.3 KB · Views: 444
  • 222195-b54ffaec0afbba6d5453a104228544fb.jpg
    222195-b54ffaec0afbba6d5453a104228544fb.jpg
    1.3 KB · Views: 679
PaxFinnica96 said:
So instead of differentiating at the end I should just leave the equations as they are like below?

View attachment 239115
No. You solve the two equations in two unknowns for the change in height in the second tank.
 
Chestermiller said:
No. You solve the two equations in two unknowns for the change in height in the second tank.

Ok, that's great I think I've managed to solve the two equations and demonstrate the proof but I'm still struggling with how best to determine the time constant - would it just be a simple matter of rearranging the model equation (the one I've just solved from the two above equations) for tau?
 
PaxFinnica96 said:
Ok, that's great I think I've managed to solve the two equations and demonstrate the proof but I'm still struggling with how best to determine the time constant - would it just be a simple matter of rearranging the model equation (the one I've just solved from the two above equations) for tau?
You already provided an equation for tau.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
8
Views
6K
  • · Replies 7 ·
Replies
7
Views
7K
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
12
Views
3K