Tank flooding time for a compartment

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SUMMARY

This discussion focuses on calculating the flooding time for a submerged compartment, considering the effects of back pressure from compressed air. The key factors include the hydrostatic pressure at the upper valve, the mass flow rates of air and water, and head losses through the valves and piping. The gas equation PV = nRT is essential for estimating the internal air pressure as the tank floods. The flood valve and vent valve are both specified as 6 inches in diameter, which impacts flow calculations.

PREREQUISITES
  • Understanding of hydrostatic pressure principles
  • Familiarity with fluid dynamics and mass flow rates
  • Knowledge of gas laws, specifically the ideal gas law (PV = nRT)
  • Experience with calculating head losses in piping systems
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  • Research methods for calculating flooding time in submerged tanks
  • Learn about fluid dynamics principles related to back pressure
  • Study head loss calculations in piping systems
  • Explore practical applications of the ideal gas law in fluid mechanics
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Engineers, fluid dynamics specialists, and anyone involved in the design and analysis of submerged tanks and fluid systems will benefit from this discussion.

arjal
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Hi can someone please help me I have been asked to calculate how long it would take to flood a compartment taking into account:

Back pressure due to the air inside the tank being compressed. This will happen as the tank floods until the point when air pressure inside the tank is the same as the hydrostatic head at the inlet to the upper valve. From this point on water will continue to enter via the bottom valve as the air leaves by the upper valve.

Please note this is underwater.

Thanks
 
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If the upper valve is open during flooding, then the tank will see a certain mass flow of air out of the upper valve and another mass flow of water into the lower valve. The net amount of air within the tank will govern the internal pressure as a function of time.

I assume the the tank is fully submerged, including the upper valve during this process. With the tank fully submerged, if the internal pressure is less than the hydrostatic pressure at the mouth of the upper valve, then water will want to enter through the top and bottom until the conditions within the tank cause a change in flow of the water in and air out.

The flow through the valves will also depend on the head losses through the valves and attached piping. The air pressure in the tank can be estimated using the gas equation PV = nRT.
 
hi thanks

the flood valve at the bottom is 6" as is the vent valve at the top. Is it possible for you to show me an example?

thanks in advance
 

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