Task: Function for the acceleration throughout a loop?

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The discussion revolves around calculating the acceleration of an object moving in a circular loop while attached to a fixed point by a rope, with an additional constant force acting on it. The task involves determining the acceleration vector at specific points and finding a function that describes this acceleration based on the angle of the object. Challenges arise due to the interaction between the centripetal force from the rope and the external force, complicating the calculations. Participants suggest redefining the coordinate system to simplify the relationship between forces and angles. The conversation highlights the complexities of energy conservation and the effects of external work on the system.
OskarBillington
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So, this seemed really fun to me until I got stuck.

THE TASK is about an object with mass m, moving in a basic (2D) coordinate system. It is attached to origo (0, 0) by a "rope" with constant length r=5. In position P0(-5, 0) it has the velocity v0=[0, -10]. Hence, the object moves around origo in a circular loop, and the force on m from the rope shall be referred to as C. There is also another (constant) force: F=[10m, 0] (m being the mass: all calculations should be done without units). F could represent a gravitational pull, to ease the comparison to a standard loop. By the terms, the mechanical energy is conserved.

First, you are asked to find the acceleration (expressed as a vector) in points (-5, 0), (0, -5), (5, 0), (0, 5). This is easily done by Newton's 2nd law: ΣF=ma⇒ either m[±v2/r, 0] (in points (-5, 0) and (5, 0), because ΣF=centripetal force=mv2/2) or m[10, ±v2/r] (in the other two points, because ΣFx=F and ΣFy=centripetal force).

FINALLY: You are now asked to find a function a(α)=[ax, ay].
- a is the acceleration vector of m.
- α is the angle, determining the position of m. Preferably, you want this to be the angle from the positive x-axis to the "rope" (counter clockwise).
- The vector function shall describe the acceleration vector of m at any position in the loop.
Good luck

Notes:

It seems that the reason why the second task is hard is because F interferes with Cx. In comparison: in the first task, F has either everything or nothing to do with C. C does of course consist of the pull from the rope, and in most positions also some push/pull from F. I can hardly explain the issue any better (at least in English), but you may anyhow find that the task is quite difficult.

An idea of mine is to define the x-/ y-axes along the velocity vector and the C vector, so that when α changes, F only rotates around m. In this redefined coordinate system: ΣFx will then depend only on the angle, and will simply* be equal to Fx (*still difficult to cover the entire 360° movement with one function). ΣFy will always equal C, again equal to mv2/r - and a function of the size v may be possible to work out. With this x-/y-perspective I suppose you will result in a vector function for a, which would then have to be modified to "rotate" back to work with the x-/y-axis definition in the original task.

I am inexperienced with the English physics terms, hence the poor or incorrect use of terminology. Please inform me on potential for improvement!
 
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Hi Oskar,

I've moved this thread to the introductory physics homework forum, but in the future please post all homework or homework-type questions in the appropriate homework forum and use the template provided when making a new thread. Thanks.
 
As the question suggests, this is just like a mass executing a vertical circle in the presence of gravity. How would you determine the speed at a given angle in that case?
 
haruspex said:
As the question suggests, this is just like a mass executing a vertical circle in the presence of gravity. How would you determine the speed at a given angle in that case?
At a given angle, I don't know. At the 4 angles in task 1 I thought I was onto something (WF=Fs=Δmv2/2). However, I just realized that, i.e., F does not add 10m*10 kinetic energy units from P0 to (5, 0), as F does work on both the speed and C all the way. Working on general velocity now...
 
OskarBillington said:
At a given angle, I don't know. At the 4 angles in task 1 I thought I was onto something (WF=Fs=Δmv2/2). However, I just realized that, i.e., F does not add 10m*10 kinetic energy units from P0 to (5, 0), as F does work on both the speed and C all the way. Working on general velocity now...
Will the string remain taut? If work is done against C, what does that imply about the string length?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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