- #1

rexregisanimi

- 43

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- Thread starter rexregisanimi
- Start date

- #1

rexregisanimi

- 43

- 6

- #2

mfb

Mentor

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How are they related to x?

There is way too much context missing to answer that.

- #3

rexregisanimi

- 43

- 6

It shouldn't matter; f is a function of x (and other variables)...

- #4

pwsnafu

Science Advisor

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It shouldn't matter; f is a function of x (and other variables)...

You can't Taylor expand around a variable. You expand around a fixed base point. That's why we write the polynomials terms as ##(x-a)^n##, i.e. expand around a.

- #5

mfb

Mentor

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It does matter. Letters without any definition are pointless.It shouldn't matter;

It is like asking "what is x+y?" You cannot answer it (apart from "it is x+y") if you have no idea what x and y are.

- #6

rexregisanimi

- 43

- 6

I was either communicating poorly or something. I found my answer.

f+df = f +(df/dx)dx + (d2f/dx2)dx2 + ... [The parenthetical terms are partials but not the differentials.]

My favorite is, "It does matter. Letters without any definition are pointless." And to think I wasted all that time learning Algebra! :/

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