Taylor Formula for two variables

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Homework Help Overview

The discussion revolves around the quadratic Taylor series for functions of two variables, specifically focusing on the notation involving the Hessian matrix. Participants are exploring the implications of the Hessian in the context of the Taylor formula and its components.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand the role of the Hessian in the Taylor series expansion. Questions include the interpretation of the transpose notation, the process of matrix multiplication, and how to derive a scalar from the expression involving the Hessian.

Discussion Status

Some participants are providing clarifications regarding the notation and the operations involved, such as matrix multiplication and transposition. There is an ongoing exploration of the concepts without a clear consensus on all aspects of the Hessian's application.

Contextual Notes

Participants express varying levels of familiarity with matrices and the specific mathematical operations required in this context, indicating a potential gap in foundational knowledge that may affect their understanding of the problem.

Juan Pablo
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I'm attempting to understand this notation (involving the Hessian) for the quadratic Taylor series for two variable.

[tex]T_2 ( \tmmathbf{x}) = f ( \tmmathbf{a}) + \nabla f ( \tmmathbf{a}) \cdot<br /> ( \tmmathbf{x - a}) + \frac{1}{2} ( \tmmathbf{x - a}) \cdot H (<br /> \tmmathbf{a}) \cdot ( \tmmathbf{x - a})^t[/tex]

where
[tex]x=(x_1,x_2)[/tex] and
[tex]a=(a_1,a_2)[/tex]
and H is the Hessian

It was given by my professor, I understand the the first part just fine (until [tex]\frac{1}{2}[/tex]). I'm not sure what to do with the Hessian there. Do I take the determinant? What does the t means? Should I transpose the vector matrix of [tex]x-a[/tex]?

I would like to put it in a more simple way that doesn't involve vectors so I can take the partial derivatives.

Any sort of guidance would be greatly appreciated.
 
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Juan Pablo said:
It was given by my professor, I understand the the first part just fine (until [tex]\frac{1}{2}[/tex]).
The 1/2 is just 1/2!.

Juan Pablo said:
I'm not sure what to do with the Hessian there. Do I take the determinant? What does the t means? Should I transpose the vector matrix of [tex]x-a[/tex]?

The dots in the expression
[tex]( \tmmathbf{x - a}) \cdot H (<br /> \tmmathbf{a}) \cdot ( \tmmathbf{x - a})^t[/tex]​
are just matrix multiplication.
 
Thanks for your input. I mentioned 1/2 as a delimiter of what I understand, of course I understand 1/2.

I'm not terrobly familiar with matrices. I do know multiplication, transpose and such but not much more. Doesn't the Hessian take a function as its argument? Does the superscript "t" mean I should transpose the matrix? How am I supposed to get an scalar function out of a function containing a matrix?

Sorry for all the questions, I'm really confused here.
 
H(a) is assumed refer to the Hessian of f at a. And yes, [tex](x-a)^t[/tex] is the transpose of (x-a).

As to getting a scalar out of this, notice that (x-a) can be thought of as a 1x2 matrix. Then we have a 1x2 matrix times a 2x2 matrix times a 2x1 matrix, which leaves a 1x1 matrix, i.e. a scalar.
 
Thanks for your help! It was really useful!
 
Juan Pablo said:
Thanks for your help! It was really useful!

You're very welcome!
 

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