Taylor Series Expansion and Radius of Convergence for $f(x)=x^4-3x^2+1$

Click For Summary
SUMMARY

The Taylor series expansion for the function \( f(x) = x^4 - 3x^2 + 1 \) centered at \( a = 1 \) is given by \( -1 - 2(x-1) + 3(x-1)^2 + 4(x-1)^3 + (x-1)^4 \). Since this Taylor series is a polynomial, it converges for all values of \( x \). Therefore, the radius of convergence is \( (-\infty, \infty) \).

PREREQUISITES
  • Understanding of Taylor series and polynomial functions
  • Knowledge of power series expansions
  • Familiarity with the concept of radius of convergence
  • Basic calculus, particularly differentiation and evaluation of functions
NEXT STEPS
  • Study the derivation of Taylor series for various functions
  • Learn about the ratio test for determining the radius of convergence
  • Explore the implications of polynomial convergence in real analysis
  • Investigate applications of Taylor series in numerical methods
USEFUL FOR

Students and professionals in mathematics, particularly those studying calculus, real analysis, or numerical methods, will benefit from this discussion.

ineedhelpnow
Messages
649
Reaction score
0
find the taylor series for $f(x)=x^4-3x^2+1$ centered at $a=1$. assume that f has a power series expansion. also find the associated radius of convergence.

i found the taylor series. its $-1-2(x-1)+3(x-1)^2+4(x-1)3+(x-1)^4$ but how do i find the radius of convergence?
 
Physics news on Phys.org
Since your Taylor series is a polynomial in $x$ (or $x-1$), it converges for all $x$. So the radius of convergence is $(-\infty, \infty)$.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 5 ·
Replies
5
Views
16K
  • · Replies 3 ·
Replies
3
Views
2K