Taylor Series for ln(x) of Degree n at 2

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Homework Help Overview

The discussion revolves around finding the Taylor polynomial for the natural logarithm function, ln(x), of degree n at the point x = 2. Participants are exploring the coefficients and patterns associated with the Taylor series expansion.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to identify a pattern in the coefficients of the Taylor series for ln(x) at x = 2, expressing confusion over the sign changes and the derivation of a general formula. Some participants question how to adapt known formulas for Pn,1(x) to Pn,2(x) for ln(x).

Discussion Status

The discussion is active, with participants sharing insights and clarifications. One participant expresses realization of a pattern after further contemplation, indicating a productive direction in understanding the coefficients.

Contextual Notes

There is mention of limited resources, as the original poster notes that only formulas for Pn,1(x) are available in their notes, which may constrain their ability to derive the necessary Taylor polynomial for ln(x) at x = 2.

ptolema
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Homework Statement



find Taylor polynomial for ln x of degree n, at 2
(Pn,2(x))

Homework Equations



Pn,1(x)= (x-1) - (x-1)2/2 + ... + (-1)n-1(x-1)n/n

The Attempt at a Solution


there doesn't seem to be an obvious pattern to this. the coefficients for n=1 to n=4 are 2, -8, 24, -64. there is a common factor of 2, yes, but this doesn't account for the sign changes. the first term is ln 2, a positive number, then the next is (x-2)/2, another positive coefficient. how can i find the formula expressed with n and x for each term?
 
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You should have in your notes or book a general formula for a Taylor series. Start by looking that up.
 
yes, i did check all my notes, but the only ones given were formulas for Pn,1(x). I'm not sure how to change it to Pn,2(x) for ln, that's what i need help with
 
ptolema said:
yes, i did check all my notes, but the only ones given were formulas for Pn,1(x). I'm not sure how to change it to Pn,2(x) for ln, that's what i need help with

How did you get that the coefficients for n=1 to n=4 are 2, -8, 24, -64? That's certainly correct if you mean 1/2, -1/8, etc. Don't you see how to get the pattern for a general coefficient from that? Probably easier than deriving it from Pn,1(x).
 
i see now! after staring at it for a bit, i finally realized the (rather obvious) trend, thanks
 

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