Taylor series representation help

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SUMMARY

The discussion focuses on finding the Taylor Series representation of the function \( f(x) = x^{1/2} \) at the point \( a = 1 \). The user attempts to derive the series expansion without using binomial coefficients, resulting in the expression \( 1 + \sum_{n=1}^{\infty} \frac{(-1)(-3)...(-(2n+1))}{2^n} \frac{(x-1)^n}{n!} \). The definition of the Taylor series is provided, emphasizing the need to compute the nth derivative of \( f(x) \) at \( a \).

PREREQUISITES
  • Understanding of Taylor Series and its mathematical definition
  • Knowledge of derivatives and their computation
  • Familiarity with series notation and summation
  • Basic algebraic manipulation skills
NEXT STEPS
  • Learn how to compute higher-order derivatives of functions like \( x^{1/2} \)
  • Study the convergence criteria for Taylor Series
  • Explore alternative series representations, such as Maclaurin series
  • Investigate the implications of using binomial coefficients in series expansions
USEFUL FOR

Students studying calculus, particularly those focusing on series expansions, and anyone looking to deepen their understanding of Taylor Series and derivatives.

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Homework Statement


Find the Taylor Series of x^(1/2) at a=1


Homework Equations


i have no idea how to do the representation, i believe our professor does not want us to use any binomial coefficients


The Attempt at a Solution


i got the expansion and here's my attempt at the representation

1+∑(1 to ∞) [(-1)(-3)...(-(2n+1))/2^n](x-1)^n/(n!)
 
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There are many different ways to "represent" a function as a series but the definition of the "Taylor series" representation of f(x) is
[tex]\sum_{n=0}^\infty \frac{f^{(n)}(a)}{n!}(x- a)^n[/tex]
where "[itex]f^{(n)}(a)[/itex]" is the nth derivative of f at x= a. Have you found the nth derivative of [itex]x^{1/2}[/itex]?
 
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