TE Waves in Rectangular Wave Guide

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unscientific
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Hi guys I'm having difficulty understanding why the boundary conditions lead to dX/dx = 0.

Why must Bx = 0 at x = 0 and x = a?


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And that is arisen from the fact that there is no magnetic dipole, i.e., the magnetic field is divergenceless. You can derive the continuity of the normal component of the magnetic field on the boundary by imaging a small pillbox on the boundary. Maybe Griffiths already described in Chap 5.
 
Thanks Achuz for noticing my mistake
 
Meir Achuz said:
B_n is continuous at a boundary, and B=0 inside a perfect conductor (which is assumed for these equations).
Therefor B_n=0 just outside the conductor.

Sorry, I don't get what you mean. If B_n is perpendicular to surface and = 0, then won't Bx = 0 and By = 0 along y-axis and x-axis correspondingly
 
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unscientific said:
Sorry, I don't get what you mean. If B_n is perpendicular to surface and = 0, then won't Bx = 0 and By = 0

Only the normal component is continuous.. so B is parallel to surface at the boundary.
 
scoobmx said:
Only the normal component is continuous.. so B is parallel to surface at the boundary.

Yes, so along x-axis, By = 0, and along y-axis, Bx = 0?