cepheid said:
In general, I think that this is correct. A warm air mass will rise and expand. When this is happening over you, the local atmospheric pressure is therefore lower. I'm guessing it's simply because you have a less dense air mass over you. Therefore it weighs less and exerts less pressure. Come to think of it, it's like suddenly having fewer air molecules per unit volume. Just as if this were happening in a container, the pressure would decrease.
Likewise, a cooler air mass will sink and contract, becoming more dense. I'm quite sure that when that happens in your area, it's referred to as a high pressure system.
Is my assessment correct?
Actually, the exact opposite is true about what you said. First of all, pressure increases with temperature, and increasing pressure or temperature causes density to go down. Hence why hotter air rises and cooler air sinks. In fact a "high pressure system" that they refer to in forcasts always have higher temperature, and low pressure systems always have lower temperature. According to the Ideal Gas Law...
PV = nRT
Where P = pressure, V = volume, n = moles, R = ideal gas constant, and T = temperature
As you can see, when pressure increases if volume and moles is kept constant, then temperature must increase as well.
You can manipulate the equation to see the effects on density...
n = \frac{m}{MM} Where m = mass, and MM = molar mass
PV = \frac{mRT}{MM}
P = \frac{DRT}{MM} Where D = density
D = \frac{P(MM)}{RT}
From this, it is clearly seen that if pressure is kept constant, increasing temperature must make density decrease
Actually, it is much easier to see the relationship between P, V, and T by using the Combined Gas law...
\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}
See for yourself by pluging in numbers.