Temperature of a Solar panel in space

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SUMMARY

The discussion centers on the thermal dynamics of photovoltaic solar panels in space, specifically analyzing two 1 square meter marble slabs, each with a mass of 1 kg, under direct sunlight. At equilibrium, the power received from the sun (PS) equals the power lost through radiation (PR), maintaining a temperature of 300K. When a photovoltaic panel and a resistive load are introduced, the net power received by the load slab increases, causing its temperature to rise, while the photovoltaic slab experiences a decrease in temperature due to power diversion. This illustrates that photovoltaic cells limit their temperature increase by converting absorbed solar energy into usable work.

PREREQUISITES
  • Understanding of thermal equilibrium principles
  • Knowledge of photovoltaic cell operation
  • Familiarity with concepts of power transfer and energy conversion
  • Basic principles of entropy in thermodynamics
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nithinyes
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Consider two 1 square meter marble slabs each of mass 1 kg floating in space facing the sun such that light from the sun incident perpendicularly on the flat faces.
us9a2bigwft51.png
At equilibrium, power received from the sun 'PS' equals the power being lost in the form of radiation 'PR'.

PS = PR (at equilibrium)

For simplicity, assume the equilibrium temperature TE = 300K.

Let us now install a photovoltaic solar panel on the right slab and resistive load on the left slab.

Assume the mass of the photovoltaic panel and resistive load be 1 kg each.

Connect the panel and load using wires and a switch of negligible mass.

4r56nn1iwft51.png
Let the new equilibrium temperature also be 300 K.

At time t = 0, the pv cell is connected to the load by closing the switch. Let the power being transmitted from pv slab to load slab be 'PPV' and all this power is consumed by the load slab.

So the net power received by load slab is PS + PPV and the net power received by pv slab is PS - PPV.

Since PS + PPV > PS - PPV,

So what happens to the temperature of the slabs?
 
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nithinyes said:
So what happens to the temperature of the slabs?
You first: what do you think happens, and why?
 
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russ_watters said:
You first: what do you think happens, and why?
I think that the power consumed at the load converts into heat and so the temperature of load slab increases.

Coming to pv slab, net power received is reduced due to diversion of some solar power to load power and so the temperature of pv slab decreases.

Am I correct?
 
nithinyes said:
I think that the power consumed at the load converts into heat and so the temperature of load slab increases.

Coming to pv slab, net power received is reduced due to diversion of some solar power to load power and so the temperature of pv slab decreases.

Am I correct?
Yup!
 
russ_watters said:
Yup!
If so, Can we say that photovoltaic cell is a device which reduces its temperature and does useful work on surroundings when it is operating?
 
nithinyes said:
If so, Can we say that photovoltaic cell is a device which reduces its temperature and does useful work on surroundings when it is operating?

Yes, but in order to avoid misconception it is better to say that it limits the increase of its temperature by doing work that would otherwise converted into heat.
 
DrStupid said:
Yes, but in order to avoid misconception it is better to say that it limits the increase of its temperature by doing work that would otherwise converted into heat.
Can you please explain it a little elaborately in terms of entropy?
 
nithinyes said:
Can you please explain it a little elaborately in terms of entropy?

Sunlight (with low entropy) is absorbed by the solar panel and converted into heat (with high entropy). If a part of the absorbed energy is converted into work (without entropy) there is less energy left to heat the panel.
 
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DrStupid said:
Sunlight (with low entropy) is absorbed by the solar panel and converted into heat (with high entropy). If a part of the absorbed energy is converted into work (without entropy) there is less energy left to heat the panel.
Thank you
 
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nithinyes said:
I think that the power consumed at the load converts into heat and so the temperature of load slab increases.

Coming to pv slab, net power received is reduced due to diversion of some solar power to load power and so the temperature of pv slab decreases.

Am I correct?
Because this is an intermediate level post I would like, for completeness, to include one complication.. The slab is made of marble which is presumably not very absorbtive (or therefore emissive). Panting (only) the sunward side of the slab black would increase its radiative equilibrium temperature. The solar cells are black and not 100% efficient and so the true answer is unknown because of these competing factors.
But the rest of the analysis is fine.
 
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