1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Temperature of a spinning and non spinning asteroid

  1. May 1, 2017 #1
    1. The problem statement, all variables and given/known data
    Consider a rapidly rotating asteroid with an albedo (reflectivity) averaged over the solar spectrum of 0.05 that orbits around a 3 solar mass star that has the same surface temperature as the Sun. The asteroid’s orbit has a semi-major axis of 15 AU. What is its equilibrium temperature? Consider a similar asteroid that does not rotate. What would the average temperature be on its star-ward side?

    2. Relevant equations

    T4=(L(1-A))/(16*pi*sigma*D2)

    L/Lsun=1.5*(M/Msun)3.5

    3. The attempt at a solution

    I plugged the mass into the second equation and got that the luminosity of the star in the problem is 70.15 solar luminosities. If I assume the semi-major axis is the average distance from the star, plugging all those numbers into the first equation gives a temperature of 205.48 K. I don't know which temperature this gives me, though, the spinning or stationary. And whichever it gives me, I'm not sure how I should go about finding the other.
     
  2. jcsd
  3. May 1, 2017 #2

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    I'm not familiar with that equation, so I do not know how it is applied. Can you post a link? But it seems to me that the star is the same temperature as the sun and has only a slightly larger radius, so its power output should only be slightly more.
    That's a bit of an assumption. Won't it spend rather longer at the greater distances? But you are not given the eccentricity, so I guess you have no choice there.
    I think the question means one that is gravitationally locked, so one day=one year.
    Because the emission law is to the fourth power, the average emission power over the surface will not be the same as the emission power at the average temperature over the surface. In the spinning case you can take the temperature as constant; in the gravitationally locked case it will be very different.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Temperature of a spinning and non spinning asteroid
  1. Spin-spin interaction (Replies: 4)

Loading...