Temperature variation of resistance

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Homework Help Overview

The discussion revolves around a problem involving the temperature variation of resistance in a copper wire. Participants are tasked with calculating the potential difference required to maintain a current of 5.0 A at two different temperatures: 20°C and 200°C.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the resistance formula R = resistivity * L/A and the application of Ohm's Law (V = IR) to find potential differences. There are questions about the values used for resistivity and temperature coefficients, as well as concerns about calculation errors.

Discussion Status

Several participants have shared their calculations and values for resistivity and temperature coefficients. There is an ongoing exploration of discrepancies in answers, with some participants confirming their results against textbook values. Guidance has been offered regarding careful arithmetic and the importance of checking calculations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is an emphasis on ensuring accuracy in calculations, particularly with respect to significant figures and powers of ten.

jsantor1
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So the problem I am working on is.. A 100 cm long copper wire of radius 0.45 cm has a potential difference across it sufficient to produce a current of 5.0 A at 20°C. Find a) What is the potential difference. b) If the temperature of the wire is increased to 200°C, what potential difference is now required to produce a current of 5.0 A

I solved part a easily by finding the resistance of the wire and plugging that into V=IR with the solution being 1.34mV.

Now for part b i used the equation R=R0[1+alpha(T-T00)] and plugged back into V=IR but my solution keeps coming out wrong... please help me out here I am totally confused...
 
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jsantor1 said:
So the problem I am working on is.. A 100 cm long copper wire of radius 0.45 cm has a potential difference across it sufficient to produce a current of 5.0 A at 20°C. Find a) What is the potential difference. b) If the temperature of the wire is increased to 200°C, what potential difference is now required to produce a current of 5.0 A

I solved part a easily by finding the resistance of the wire and plugging that into V=IR with the solution being 1.34mV.

Now for part b i used the equation R=R0[1+alpha(T-T00)] and plugged back into V=IR but my solution keeps coming out wrong... please help me out here I am totally confused...

Where did you get your first answer? What is the driving potential?
 
The first part you use R= resistivity* L/A. This gives you the resistance and with the currecnt use V=IR to solve for potential difference...
 
anyone?...
 
jsantor1 said:
The first part you use R= resistivity* L/A. This gives you the resistance and with the currecnt use V=IR to solve for potential difference...

I get a different answer for the initial resistance then. I used 16.8 nΩm and I get 3.73 x 10-4Ω.

What value of α are you using?
 
well my answer is correct according to the book...the value for the resistivity of copper I am using is 1.7E-8
 
jsantor1 said:
well my answer is correct according to the book...the value for the resistivity of copper I am using is 1.7E-8

Yes. You're right. I made an error calculating the area. Sorry.

Now what are you using for your temperature α ?

I have 3.9 x 10-3 per degree C for copper.
 
That's what I'm using as well, getting a new resistance of .04824 and then getting a potential difference of 241.24mV which is coming out wrong for some reason
 
jsantor1 said:
That's what I'm using as well, getting a new resistance of .04824 and then getting a potential difference of 241.24mV which is coming out wrong for some reason

Using the calculator at
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/restmp.html

I get 4.56 x 10-4Ω (using the 2.68 x 10-4 Ω for 20 C)

That yields 2.28 mV.
 
  • #10
hmm that worked..do u know why my calculator is not computing these correctly?
 
  • #11
jsantor1 said:
hmm that worked..do u know why my calculator is not computing these correctly?

You have to be careful with the powers of 10. Looks like you might have dropped a 0 somewhere in entering the numbers. Sometimes these problems unfortunately become more about arithmetic than physics. Just be careful is the only advice I can give, but then I guess you already know that.
 
  • #12
thank you...
 

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