Tension between two cables, not sure what to do.

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SUMMARY

The discussion focuses on calculating the maximum traction force and tension in cables for a patient using a Stryker frame in spinal injury treatment. The maximum traction force calculated is 686N based on a static friction coefficient of 0.725 for a 96.5kg patient. The user struggles with determining the tension in each cable attached to the neck collar, indicating a need for clarity in analyzing forces and free body diagrams.

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  • Understanding of Newton's First Law of Motion
  • Knowledge of static friction and its calculation
  • Ability to analyze free body diagrams
  • Familiarity with vector components in physics
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  • Study the principles of free body diagrams in physics
  • Learn about tension forces in systems with multiple cables
  • Explore the application of static friction in real-world scenarios
  • Review vector decomposition techniques for force analysis
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Physics students, healthcare professionals involved in spinal injury treatment, and anyone interested in understanding the mechanics of traction devices like the Stryker frame.

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Homework Statement


In treating spinal injuries, it is often necessary to provide some tension along the spinal column to stretch the backbone. One device for doing this is the Stryker frame, illustrated in part (a) of the figure. A weight is attached to the patient (sometimes around a neck collar, as shown in part (b) of the figure), and friction between the person's body and the bed prevents sliding.

PART A: If the coefficient of static friction between a 96.5kg patient's body and the bed is 0.725, what is the maximum traction force along the spinal column that can provide without causing the patient to slide?

PART B: Under the conditions of maximum traction, what is the tension in each cable attached to the neck collar? [Picture is attached]

Homework Equations


Newtons first law ƩF=0 in equilibrium.

The Attempt at a Solution



This is for Mastering Physics btw.

I was able to find Part A: with T=Fs=μmg=(.725)(96.5)(9.8)=686N

But I am having trouble with part B. I see that the angles are equal so I assume that they are sharing equal tension. I broke them down by x and y components and found the magnitude but that was incorrect, I also used just the y component and that was incorrect as well. If someone could point me in the right direction that would help so much!
 

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Does this look right?
 

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  • tension061.jpg
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Definitely! Thanks, I definitely have to start focusing more on the free body diagrams.
 

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