Tension in Rope: Truck Towing 1T Car Up Hill

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Homework Help Overview

The problem involves a truck towing a 1.00*10^3 kg car up a hill at a constant speed, with the hill inclined at 5 degrees and the towing rope at 10 degrees to the horizontal. The participants are exploring the dynamics of the forces involved, particularly the tension in the rope, while neglecting friction.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to consider the sum of the x and y components of forces, questioning whether they should equal zero due to the constant speed. There is consideration of using different coordinate systems to analyze the forces acting on the car.

Discussion Status

The discussion is ongoing, with participants providing insights about the forces acting on the system and the implications of constant speed on the forces' components. Some guidance has been offered regarding calculating the normal force and taking components along the line of the rope.

Contextual Notes

Participants note the complexity of the problem due to the angles of the forces involved and the challenge of ensuring all components balance correctly. There is an acknowledgment of the need to clarify the relationships between the forces acting on the car and the truck.

milo7979
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A truck is towing a 1.00*10^3 kg car at a constant speed up a hill that makes an angle of 5degrees with respect to the horizontal. A rope (negligable) is attached to the truck at an angle of 10 degrees with respect to the horizontal. Neglect friction. What is the tension in the rope?
I'm not sure if the sum of the x and y components should be zero or not?
 
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milo7979 said:
A truck is towing a 1.00*10^3 kg car at a constant speed up a hill that makes an angle of 5degrees with respect to the horizontal. A rope (negligable) is attached to the truck at an angle of 10 degrees with respect to the horizontal. Neglect friction. What is the tension in the rope?
I'm not sure if the sum of the x and y components should be zero or not?

Hi milo7979! Welcome to PF! :smile:

Constant speed means zero acceleration …

so, yes, the sum of the components in any direction must be zero. :smile:

(though you might find it easier to use components along the slope :wink:)
 
i thought about using different coordinates, but only one of the forces will be on the axis because there are three forces with different angles with respect to the horizontal. I can't seem to get all of the y components to equal zero. The y component of the normal force I assume is the same magnitude as the weight (1.0*10^3 * g= 9.8*10^3N), but there is still a y component to the Force from the truck. W and y component of N equal zero, so what am I missing?
 
Last edited:
milo7979 said:
i thought about using different coordinated, but only one of the forces will be on the axis because there are three forces with different angles with respect to the horizontal.

Yes, there are three forces, and two of them are along the slope and perpendicular to it … :wink:
 
I don't think that two of the forces are along the x and y axis. N is perpendicular to the hill which is 5 degrees to the left of vertical, W which is straight down the vertical and F of truck pulling the car is 10 degrees above horizontal.
 
milo7979 said:
I don't think that two of the forces are along the x and y axis. N is perpendicular to the hill which is 5 degrees to the left of vertical, W which is straight down the vertical and F of truck pulling the car is 10 degrees above horizontal.

oh, sorry :redface:

I misread it …

ok, the force you want is the tension in the rope, so calulate the normal force, and then take components of everything along the line of the rope. :smile:
 

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