Tension in string at a point on a frame

[LeafMuncher]

Homework Statement

Hi all. What concerns me here is that it's worth 10 marks, but the solution I've tried only takes 2 steps. Am I missing some relation between the frame support and the pulley altering the components of the tension, or is the solution really just a basic trig conversion?

Homework Equations

F = mg
Tx = mg*sin(theta)

The Attempt at a Solution

using the above conversions I get the tension as 65kg*9,8m/s^2 = 637N
Then just convert using the 1/1 ratio as 45deg, giving Tx and Ty = 637*sin(45) = 450.4N

 

[nrqed]

Homework Statement

Hi all. What concerns me here is that it's worth 10 marks, but the solution I've tried only takes 2 steps. Am I missing some relation between the frame support and the pulley altering the components of the tension, or is the solution really just a basic trig conversion?

Homework Equations

F = mg
Tx = mg*sin(theta)

The Attempt at a Solution

using the above conversions I get the tension as 65kg*9,8m/s^2 = 637N
Then just convert using the 1/1 ratio as 45deg, giving Tx and Ty = 637*sin(45) = 450.4N

Your solution is correct. Good job.