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Tension in string at a point on a frame

  1. Nov 8, 2015 #1
    1. The problem statement, all variables and given/known data
    btMUsJA.jpg
    Hi all. What concerns me here is that it's worth 10 marks, but the solution I've tried only takes 2 steps. Am I missing some relation between the frame support and the pulley altering the components of the tension, or is the solution really just a basic trig conversion?

    2. Relevant equations
    F = mg
    Tx = mg*sin(theta)
    3. The attempt at a solution
    using the above conversions I get the tension as 65kg*9,8m/s^2 = 637N
    Then just convert using the 1/1 ratio as 45deg, giving Tx and Ty = 637*sin(45) = 450.4N
     
  2. jcsd
  3. Nov 8, 2015 #2

    nrqed

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    Your solution is correct. Good job.
     
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