Calculating Tension in a Suspended Rope with a 50kg Weight

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SUMMARY

The discussion centers on calculating the tension in a suspended rope supporting a 50 kg weight and a rope weighing 100N. The tension at the top of the rope, connected to the ceiling, is determined to be 600N, which includes both the weight of the rope and the weight of the suspended mass. The tension at the bottom of the rope, where the weight is attached, is calculated to be 500N. These calculations assume a gravitational acceleration of 10 m/s².

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  • Understanding of basic physics concepts, specifically tension and weight.
  • Knowledge of gravitational acceleration (g = 10 m/s²).
  • Familiarity with unit conversions, particularly between mass (kg) and weight (N).
  • Basic algebra skills for calculating forces and tensions.
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  • Study the principles of static equilibrium in physics.
  • Learn about the effects of different weights on tension in various types of ropes.
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  • Investigate real-world applications of tension calculations in engineering and construction.
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Students in physics, engineers working with structural designs, and anyone interested in understanding the mechanics of tension in ropes and cables.

SakuRERE
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[moderator: text edited to change the phrasing.]

There is a question that that says: a 50 kg weight is suspended from the bottom part from a rope.

If the rope has a weight of 100N. Then what is the tension at each end of the rope( the top part connected to the ceiling and the bottom part to the weight)?

my answer is like that
At the top: the tension is equal to the weight of the rope and the weight so it would be :
100N +500N= 600 N ( g=10)
And at the bottom it’s:
Just the weight, so 500 N. Am i right?
 
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Yes.
 
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PeroK said:
Yes.
Appreciate your quick response
Thanks^^
 

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