How Do You Solve the Tension Problem in a Multi-Mass System?

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The discussion addresses solving the tension problem in a multi-mass system involving three blocks being pulled by a force of 887 N on a frictionless surface. The equations of motion for the blocks are outlined, highlighting the relationships between tensions T1 and T2 and the masses m1, m2, and m3. A participant attempts to solve for tensions using substitution but encounters difficulties with the provided options. The suggestion is made to calculate the net force acting on m2 and divide the total force by the combined mass of all blocks to determine acceleration. This approach aims to clarify the relationships and resolve the tension equations effectively.
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Tension problem!

Homework Statement


Consider a force F = 887 N pulling 3 blocks
of masses m1 = 9 kg, m2 = 16.9 kg, and
m3 = 26.1 kg along a frictionless horizontal
surface.
The tension of the strings are T1 and T2 (see
sketch).
The equation of motion of m2 is given by
1. T1 − T2 = m1 a .
2. T1 − T2 = m2 a .
3. T1 = m2 a .
4. T1 − T2 = (m1 +m3) a .
5. T1 + T2 = m1 a .
6. T1 = (m1 + m3) a .
7. T1 + T2 = m2 a .
8. T1 = m1 a .
9. T1 + T2 = (m1 +m3) a .


Homework Equations



F=ma

The Attempt at a Solution


T1 = m2a
T2 = m3a
When I try to solve through substitution, I don't get any of the choices above.
What do i do next?
 

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Net force acting on m2 is T1 - T2.
 


Divide the force by all of the masses combined (m1+m2+m3) and this will give you the acc.

Just FYI for the first part of the problem
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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