Tension on two cables holding a weight

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bran8015
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Homework Statement



A 18.0 kg spotlight is suspended 2.40m below a horizontal pole by two 3.90m long cables that angle upward at equal angles and reach from the top of the light to either end of the horizontal pole.


Homework Equations



The only equation I have for tension is T=[tex]\mu[/tex]*m*g/(cos[tex]\vartheta[/tex]+[tex]\mu[/tex]sin[tex]\vartheta[/tex])

The Attempt at a Solution


My problem is [tex]\mu[/tex] stands for the static friction, which there is none. Do I still need to use this equation or is there a different one I don't know about. Thanks!
 
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Tension is just the force that a string or cable pulls with. You need a "free body diagram" showing the 3 forces acting on the load, with angles. Then you write
"sum of the forces = 0" for the vertical direction (and perhaps for the horizontal direction separately). The tension forces must be separated into their horizontal and vertical components to fit into these equations.
 
Thanks, I was making it way to difficult.