Terminal Speed in Projectile Motion under Air Resistance

Click For Summary
SUMMARY

The discussion centers on calculating terminal speed in projectile motion under air resistance, specifically addressing a terminal speed of 43 m/s. The equation for acceleration in the y-direction is given as ay = -g + αvy, where α = K/m. The user queries whether to consider the vertical velocity (vy) as equal to the terminal speed squared (432) or to compute it separately. Additionally, the implications for the horizontal component of velocity at terminal speed are explored.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with projectile motion concepts
  • Knowledge of air resistance and drag forces
  • Basic calculus for solving differential equations
NEXT STEPS
  • Study the derivation of terminal velocity in fluid dynamics
  • Learn about the effects of drag coefficient on projectile motion
  • Explore numerical methods for solving motion equations under air resistance
  • Investigate the relationship between horizontal and vertical components of velocity at terminal speed
USEFUL FOR

Physics students, educators, and anyone interested in the dynamics of projectile motion and air resistance effects.

th4450
Messages
38
Reaction score
0

Homework Statement


Terminal speed = 43 m s-1

Homework Equations


Acceleration in y direction when ball falling down: ay = - g + [itex]\alpha[/itex]vvy
where [itex]\alpha[/itex] = K/m
and v = (vx2 + vy2)^0.5

The Attempt at a Solution


Putting ay = 0 as there is no acceleration when terminal speed occurs.
However, is vvy equal to v2, i.e. 432 here?
Or do I have to compute its velocity in the y direction?
 
Physics news on Phys.org
When at terminal speed (near as dammit), what can you say about the horizontal component?
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
3K
Replies
40
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 37 ·
2
Replies
37
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
1
Views
2K
Replies
6
Views
3K