Textbook Mistake: Ionization Energy of He+

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Discussion Overview

The discussion revolves around the ionization energy of the He+ ion compared to that of a hydrogen atom, exploring the relationship between nuclear charge and ionization energy within the context of quantum mechanics and electrodynamics.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions the textbook's claim that the ionization energy of He+ is four times that of hydrogen, suggesting it should only double based on the potential energy formula for two charges.
  • Another participant asserts that the textbook is correct, stating that the energy required for ionization depends on the square of the number of protons.
  • A participant seeks clarification on why the energy would depend on the square of the number of protons, referencing the potential energy equation.
  • Another reply explains that in the Bohr model, the effective radius is inversely proportional to the number of protons, leading to the conclusion that total energy is proportional to the square of the nuclear charge.
  • A later participant expresses understanding of the explanation provided regarding the relationship between nuclear charge and ionization energy.

Areas of Agreement / Disagreement

There is disagreement regarding the relationship between nuclear charge and ionization energy, with some participants supporting the textbook's claim while others challenge it. The discussion remains unresolved as different viewpoints are presented without consensus.

Contextual Notes

The discussion involves assumptions about the applicability of the Bohr model to multi-electron atoms and the simplifications made in relating potential energy to ionization energy.

p.tryon
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This is a question from a chem textbook but it seems relevant to electrodynamics/quantum mechanics. The energy to ionize a hydrogen atom in its ground state is given by:

En = -Rhc / n2

Ei = Rhc (because the electron is being taken to infinity) = 1312kJ/mol

The book claims that to ionize a He+ ion (which has 2 protons in its nucleus) would require 4 times the amount of energy. However the potential energy of two charges separated by distance r is given by

P.E. = kq1q2/r

Since the charge of an electron is the same in both cases (the H atom and the He ion) and the nuclear charge is doubled in the case of the He+ ion- shouldn't the P.E. at infinity (therefore ionization energy) also double? (not quadruple as the book claims!)
 
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The book is correct. To a rough approximation, the energy depends on the square of the number of protons.
 
Thanks for your reply. Why does it depend on the square of the number of protons? Doesn't that contradict the equation below?

P.E. = kq1q2/r
 
Hi p.tryon,

You may find it useful to think about how the effective value of r in your equation depends on the number of protons.
 
p.tryon said:
Thanks for your reply. Why does it depend on the square of the number of protons? Doesn't that contradict the equation below?

P.E. = kq1q2/r
No, there's no contradiction. In the Bohr model of the atom, realize that r is inversely proportional to Z (the number of protons) so the total energy ends up being proportional to Z². (You might want to review how energy levels are derived in the Bohr model, which is admittedly only an approximation for multi-electron atoms. But it's OK for this purpose with helium, since there are only two electrons.)
 
Hello! Wow I see thank you! That makes sense
 

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