The applied and friction forces of a particle

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Homework Help Overview

The problem involves a particle of mass 14 kg sliding along a wire in a horizontal plane, with a coefficient of dynamic friction of 0.6. The wire's equation indicates it is at a 60-degree angle with the X-axis, and the particle experiences a constant acceleration of 2 m/s². The task is to determine the magnitude of an applied force acting parallel to the X-axis.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the forces acting on the particle, including the applied force, normal force, gravitational force, and frictional force. There are questions about the directions of these forces and the interpretation of the wire's orientation.

Discussion Status

Some participants have attempted calculations based on the forces involved, while others have raised concerns about the assumptions made regarding the directions of the forces and the setup of the problem. There is an ongoing exploration of the correct interpretation of the wire's angle and the forces acting on the particle.

Contextual Notes

There is confusion regarding the orientation of the wire and the relationship between the wire and the horizontal plane, as well as the nature of the friction involved. Some participants suggest that the friction may be between the particle and the wire rather than the ground.

Edd988
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Homework Statement


A particle of mass 14kg, slides along a straight wire in a horizontal plane. The coefficient of dynamic friction u=0.6 The equation of the line of the wire is y=3√x so that the angle between the wire and the X-axis is 60 degrees.

The particle accelerates with a constant acceleration whose magnitude is a=2 At time t=3s the particle is at A. The acceleration is produced by an applied force P acting parallel to the X-axis.

(b) Show that the magnitude of P is P = 220.8 Newtons

Homework Equations


F=ma
F=UR (U is coefficient of dynamic friction and R is R=mgcos(x))

The Attempt at a Solution



P-F=ma
F=UR
P=ma + F
F=0.6*mgcos(theta) = 41.202
P=14*2 + 41.202
P=69.202
[/B]
 
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A few problems there.
P and a are not in the same direction, so P-F=ma is wrong.
The wire is horizontal, so mg cos(theta) is wrong.
What are all the forces on the particle, and in what directions do they act?
 
The normal force acts perpendicular to the wire, the gravity force acts downward to the particle, the applied force will push the particle, and the friction force will act in the opposite way.
I though the plane was horizontal and the angle between the wire and the plane is 60 degree?
 
Edd988 said:
The normal force acts perpendicular to the wire, the gravity force acts downward to the particle, the applied force will push the particle, and the friction force will act in the opposite way.
I though the plane was horizontal and the angle between the wire and the plane is 60 degree?

The wire is also horizontal, it makes 60 degree angle with the x axis.
 
I guess, the wire is at 60 degree from horizontal.
 
Edd988 said:
The normal force acts perpendicular to the wire
Right, but that leaves a range of possibilities for the direction.
Edd988 said:
the applied force will push the particle
Yes, but in which direction does P act in relation to (a) the horizontal plane and (b) the x-axis (c) the wire?
Edd988 said:
friction force will act in the opposite way
Opposite to what exactly? I.e., which direction is the force of friction in relation to (a) the horizontal plane and (b) the x-axis (c) the wire?
 
jatin9953 said:
I guess, the wire is at 60 degree from horizontal.
That's not what it says:
Edd988 said:
along a straight wire in a horizontal plane
 
I tried it, with conservation of energy and got the answer close to 208N
 
jatin9953 said:
I tried it, with conservation of energy and got the answer close to 208N
I get a rather larger result. The tricky part is calculating the normal force correctly.
 
  • #10
The result given in the problem is obtained if friction exist between the ground and the object only. The object slides along the wire, on the ground.
 
  • #11
ehild said:
The result given in the problem is obtained if friction exist between the ground and the object only. The object slides along the wire, on the ground.
Hmm... there's nothing in the OP about a ground, and it sounds like the friction is between particle and wire. Edd, have you stated the problem exactly as given to you?
 

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