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The Average Force Exerted on the Ball

  1. Oct 16, 2009 #1
    1. The problem statement, all variables and given/known data

    A 1.83 kg steel ball strikes a massive wall at
    4.08 m/s at an angle of 67.6◦ with the plane of
    the wall. It bounces off with the same speed
    and angle. If the ball is in contact with the wall for
    0.105 s , what is the magnitude of average
    force exerted on the ball by the wall? Answer
    in units of N.

    2. Relevant equations

    F= ΔP/Δt
    J_y=ΔP=0
    J_x=ΔP=P_f - P_i

    3. The attempt at a solution

    I solved for the ΔP in the x direction, and divided that by the time they gave me.

    F= (2*m*v*cos(theta))/Δt
    F= (2*1.83*4.08*cos(67.6))/.105 = 7.92562
     
  2. jcsd
  3. Oct 16, 2009 #2
    nevermind.. I had my calculator in radians...
     
  4. Oct 16, 2009 #3

    rl.bhat

    User Avatar
    Homework Helper

    Hi Tavia15, welcome to PF.
    The angle is with the plane of the wall.
    So you have to replace cosθ by sinθ.
     
  5. Oct 16, 2009 #4
    Thank you:)
     
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