The Average Force Exerted on the Ball

[Tavia15]

Homework Statement

A 1.83 kg steel ball strikes a massive wall at
4.08 m/s at an angle of 67.6◦ with the plane of
the wall. It bounces off with the same speed
and angle. If the ball is in contact with the wall for
0.105 s , what is the magnitude of average
force exerted on the ball by the wall? Answer
in units of N.

Homework Equations

F= ΔP/Δt
J_y=ΔP=0
J_x=ΔP=P_f - P_i

The Attempt at a Solution

I solved for the ΔP in the x direction, and divided that by the time they gave me.

F= (2*m*v*cos(theta))/Δt
F= (2*1.83*4.08*cos(67.6))/.105 = 7.92562

 

[Tavia15]

nevermind.. I had my calculator in radians...

 

[rl.bhat]

Hi Tavia15, welcome to PF.
The angle is with the plane of the wall.
So you have to replace cosθ by sinθ.

 

[Tavia15]

Thank you:)