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Homework Help: The Average Force Exerted on the Ball

  1. Oct 16, 2009 #1
    1. The problem statement, all variables and given/known data

    A 1.83 kg steel ball strikes a massive wall at
    4.08 m/s at an angle of 67.6◦ with the plane of
    the wall. It bounces off with the same speed
    and angle. If the ball is in contact with the wall for
    0.105 s , what is the magnitude of average
    force exerted on the ball by the wall? Answer
    in units of N.

    2. Relevant equations

    F= ΔP/Δt
    J_x=ΔP=P_f - P_i

    3. The attempt at a solution

    I solved for the ΔP in the x direction, and divided that by the time they gave me.

    F= (2*m*v*cos(theta))/Δt
    F= (2*1.83*4.08*cos(67.6))/.105 = 7.92562
  2. jcsd
  3. Oct 16, 2009 #2
    nevermind.. I had my calculator in radians...
  4. Oct 16, 2009 #3


    User Avatar
    Homework Helper

    Hi Tavia15, welcome to PF.
    The angle is with the plane of the wall.
    So you have to replace cosθ by sinθ.
  5. Oct 16, 2009 #4
    Thank you:)
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