The Change in velocity and direction.

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SUMMARY

The acceleration of a bullet shot horizontally at 40 m/s, which changes to a velocity of 44.5 m/s at an angle of 26.1 degrees below the horizontal over a time span of 2.0 seconds, can be calculated using the formula a = Δv / t. The initial velocity (vi) is 40 m/s, and the final velocity (vf) is 44.5 m/s. The correct calculation yields an acceleration of 2.25 m/s², not 41 m/s² as previously attempted.

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  • Knowledge of acceleration calculations
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Gprime
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Homework Statement


What is the acceleration of a bullet that was shot at 40.m/s in the horizontal and then changed to a velocity of 44.5m/s at 26.1* below the horizontal in a time of 2.0 seconds.

Homework Equations



vf-vi= delta v a= delta v / time

The Attempt at a Solution



I have tried to solve using head to tail diagram and i ended up 41m/s2. I am not entirely sure of this answer, and I have a test next morning on this.
 
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That's not correct. Show how you got that result.
 

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