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audiowize

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I am looking into proving that the Chinese Remainder Theorem will work for two pairs of congruences IFF a congruent to b modulo(gcd(n,m)) for

x congruent to a mod(n) and x congruent to b mod(m).

I have gotten one direction, that given a solution to the congruences mod(m*n), then a congruent to b mod(gcd(m,n)).

My issue is going the other way, given a congruent to b mod(gcd(m,n)), show a solution to the congruences exists mod(m*n).

Can anybody help me with a start? I tried expressing the relationship between a and b and using that to determine what x would have to be, but I'm not convinced of the results.