- #1
roam
- 1,271
- 12
Homework Statement
http://img580.imageshack.us/img580/7492/50177994.jpg
The Attempt at a Solution
I first attempt part (a) since both parts are similar:
(a) I need to know "v" in order to use the following equation to find the de Broglie wavelength:
[itex]\lambda = \frac{h}{p} =\frac{h}{mv}[/itex]
So I first found the kinetic energy of a N2 molecule:
[itex]K=3(1.38065 \times 10^{-23})(300)/2 = 6.21292 \times 10^{-21} \ J[/itex]
So I used the following relationship to work out v
[itex]K=\frac{1}{2} mv^2 \implies v = \sqrt{\frac{2K}{m}} = \sqrt{\frac{2(6.213 \times 10^{-21})}{28(1.6605 \times 10^{-27})}}[/itex]
[itex]\therefore \ v=516.96 \ m/s[/itex]
[itex]\lambda = \frac{6.63 \times 10^{-34}}{(28(1.6605\times 10^{-27})\times 516.96)} = 2.7593 \times 10^{-11}[/itex]
My answer seems wrong because this is 0.0275 nanometers (or 27.589 picometers) which is in the X-ray region of the spectrum! So what did I do wrong?
Also the question says "compare this with the diameter (less than 1 nm) of the molecule", what does that mean? My value for λ is shorter than the diameter of the molecule which doesn't sound right.
Any help is greatly appreciated.
Last edited by a moderator: