The distance between the incident point and the refracted point

[zade70]

Homework Statement

http://s32.postimg.org/4urcaq0xx/image.png
The incidence angle of a light ray over a tile of glass with dy faces parallel is pi/3 rad. Find the distance between the incidence point and the refraction one of the ray with the tile, if the distance between these rays is 0.7 cm.

Homework Equations

sina/sinb=n2/n1

The Attempt at a Solution

sin pi/3/sinb=1.5/1 sinb=1/3
tga=sqrt (2)/2 x=0.7*sqrt(2)/2=0.5

 

[BvU]

Hi Zade,
Your post is a bit hard to follow, since you don't list the meanings of the symbols you use - and I don't see any in the drawing (which suggests 60 degrees is halfway between 0 and 90 degrees ?). Furthermore $$\sin{\pi\over 3}\ne {1\over 2}$$

You don't really ask a question and end your post with '=0.5'. Do you think the distance the exercise asks for is 0.5 cm ?

 

[Merlin3189]

Perhaps it would help if you marked on your diagram (or on a diagram); the 0.7cm and the distance to be calculated.

You don't mention any refractive indices: are you assuming air=1 (I assume it's air) and glass = 1.5 ?