The electric field between infinte plates?

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Homework Help Overview

The discussion revolves around the electric field between two infinite charged plates located at X=5 and X=-5, with a spatial charge density described by a quadratic function of X. The original poster seeks to derive the expression for the electric field in the region between the plates.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the applicability of Gauss's law to the problem, with some questioning the results obtained when integrating the charge density. There is an exploration of the relationship between the charge density and the resulting electric field.

Discussion Status

Some participants have provided insights regarding the use of Gauss's law, while the original poster has acknowledged a mistake in their earlier reasoning. The discussion appears to be moving towards a clearer understanding of the problem, though no consensus has been reached.

Contextual Notes

There is a mention of the electric field being zero outside the plates, which may influence the interpretation of the problem. The original poster's reference to a specific answer suggests a potential expectation for a particular form of the electric field expression.

axcelenator
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Two infinite plates are in the (x,y,z) space. one in X=5 and the second in X=-5. they are charged with superficial density SIGMA. Between them there is a spatial density P. P=A*X^2(X is the variable and A is constant. out the space(for example=X=10 or x=-10) the Electric field is 0.
I have to find the expression for the field(for every x and x) between the plates. How do I do that?
The answer is E=(4/3)(∏)K*A(X^3)

Thanks
 
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Gausses law.
 


gauss not works here. if i use it, it gives me ...x^2
 


axcelenator said:
gauss not works here. if i use it, it gives me ...x^2

How do you get [itex]x^2[/itex] when you use Gauss's law? Remember, you have to integrate the charge density. So, what is the integral of [itex]\rho=Ax^2[/itex]? Its definitely not proportional to [itex]x^2[/itex].
 


thanks! I've figured out my mistake. its fine
 

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