The electric potential difference created by point charges.

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SUMMARY

The discussion centers on calculating the distance a charged particle travels before coming to a stop when influenced by a fixed charge. A charge of -3.00 C is stationary, while a particle with a mass of 7.20x10^-3 kg and a charge of -8.00 C is projected towards it at an initial speed of 65.0 m/s. Participants emphasize the importance of using conservation of energy rather than kinetic energy to solve the problem, suggesting that the initial total energy must be expressed to determine the particle's deceleration and distance traveled.

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xkelleh
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Homework Statement




A charge of -3.00 C is fixed in place. From a horizontal
distance of 0.0450 m, a particle of mass 7.20x10^-3 kg and charge
-8.00 C is fired with an initial speed of 65.0 m/s directly toward the
fixed charge. How far does the particle travel before its speed is zero?



Homework Equations



My question is where do I go from KE or really how would I start this problem off?



The Attempt at a Solution



I thought that it should start off with KE so I put 1/2mv^2
 
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You don't need kinetic energy.

First you need to find the rate of acceleration (deceleration, in this case)

Force = mass*acceleration = (charge)*electron field.

Solve for acceleration.

Then use a kinematics equation to find the time.

V(final) = V(initial)*time + 1/2 (acceleration)(time squared)
 
Welcome to Physics Forums, xkelleh and Ifedayo.

Ifedayo said:
You don't need kinetic energy.

First you need to find the rate of acceleration (deceleration, in this case)

Force = mass*acceleration = (charge)*electron field.

Solve for acceleration.

Then use a kinematics equation to find the time.

V(final) = V(initial)*time + 1/2 (acceleration)(time squared)

The acceleration is not constant, so that won't work. Please watch how much help you give in the future, and let the OP do most of the thinking.

Conservation of energy is the key here. xkelleh, you could start by writing an expression for the initial total energy.
 

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