The force LRO experiences due to moons gravity?

AI Thread Summary
The discussion centers on calculating the gravitational force experienced by the Lunar Reconnaissance Orbiter (LRO) due to the Moon's gravity. Using the formula Fg = (GMm)/r^2, the user calculated the force to be approximately 2688.48 N, while the book states the answer is 2.83 x 10^3 N. The discrepancy arises from the mass of the Moon being provided with insufficient precision. The method used for the calculation is correct, but a more accurate mass for the Moon would yield a result closer to the book's answer. Overall, the conversation emphasizes the importance of significant figures in scientific calculations.
Rijad Hadzic
Messages
321
Reaction score
20

Homework Statement


The Lunar Reconnaissance Orbiter (LRO) with mass m= 1850, maps the surface of the moon from an orbital altitude of 50 km. what are the magnitude and direction of the force the LRO experiences due to the moons gravity?

Homework Equations


Fg = (GMm)/r^2

The Attempt at a Solution


First I started by changing the units to SI
Mass of moon M = .07x10^24 kg
Mass of orbiter m = 1850 kg
Gravitational constant = 6.637 x 10^-11

the radius = (radius of moon + orbital altitude ) = 1.738 x 10^6 (value from my book) + 50,000 =
1788000

Now I just use the formula: F_g = (6.637x10^{-11})(.07x10^24)(1850) / 1788000^2 = 2688.478434 N

but my books answer is 2.83 x 10^3 N

I don't understand what I did wrong as my answer comes from the formula... is there some trick I am missing??
 
Physics news on Phys.org
You used the mass of Moon with one significant figure. Why do you expect your result to be accurate to more than that?
 
  • Like
Likes Buzz Bloom
I see what you mean. Does the method I am using right though?

Sucks that my book would give me mass that would give an inaccurate answer..
 
The method is fine.
With a more precise mass for the Moon the answer will get closer to the book's answer.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top