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As a thought experiment, let us say we have two photons, photon A and photon B. Now our two lovely quanta of electromagnetic radiation are special, because they have been entangled after an atomic cascade. After the atomic collision we immediately trap our two photons and we place each one of them in separate jars. These jars a made perfectly for the transportation of single photons, so that they cannot escape by any means besides opening the lid. Now we place the jar containing photon A on a rocket ship and we fly it to the nearest black hole, while the other stays in a lab. The astronauts on the rocket ship float out of the ship, with the jar in hand, up to the black hole. The astronauts then release the A photon so that it falls directly into the black hole. Back at the lab is photon B still entangled with photon A, who is now taking an exciting trip through the even horizon and onto the singularity.

So my question to you, dear reader, is what do the scientist at the lab observe about photon B while photon A is taking its trip? Since information from quantum entanglement is non-local and, as so far observed, is instantaneous then the information about photon A should be transmitted to photon B. Right??

-Do they not observe anything? Just as watching photon A fall through the event horizon would take an infinitely long time

-Does the observed photon vanish out of existence as its particle twin is annihilated at the singularity?

-Does the quantum bond between the two photons shatter and the photon B no longer becomes a vessel of information for photon A?

So what happens????

Your comments and consideration are much appreciated. Thank you!