The hydrostatic equilibrium equation including temperature, T(z)

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SUMMARY

The discussion focuses on modeling the lower atmosphere of Venus using the hydrostatic equilibrium equation and the adiabatic lapse rate. The atmospheric pressure at the surface is 90 bars (9000 kPa) and decreases to 1 bar (100 kPa) at the cloud deck, with a temperature of approximately 350 K. The adiabatic lapse rate is confirmed as -8 K km-1, and the hydrostatic equilibrium equation is expressed as ΔP = -ρ Δz g. The challenge lies in incorporating the temperature variation T(z) into the hydrostatic equation, leading to the expression ΔP = -ρ Δz (cp/z)(T0 - T(z)).

PREREQUISITES
  • Understanding of hydrostatic equilibrium equations
  • Familiarity with adiabatic lapse rates
  • Knowledge of atmospheric pressure and temperature relationships
  • Basic calculus for integrating differential equations
NEXT STEPS
  • Study the derivation of the hydrostatic equilibrium equation in atmospheric science
  • Learn about the implications of the adiabatic lapse rate in planetary atmospheres
  • Explore the integration techniques for differential equations in thermodynamics
  • Investigate the specific heat capacity (cp) and its role in atmospheric modeling
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This discussion is beneficial for atmospheric scientists, planetary scientists, and students studying thermodynamics and fluid dynamics in relation to planetary atmospheres.

ndgoodburn
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Homework Statement


In this problem, you'll model the lower atmosphere of Venus. The atmospheric pressure reaches 1 bar (100 kPa) in the middle of the dense cloud deck, where T ~ 350 K. At the surface, the pressure is 90 bars (9000 kPa). From the surface to the 1 bar level, the temperature T(z) decreases at a rate of dT/dz = -8 K km^{-1}, close to the adiabatic lapse rate of -8 K km^{-1}.

(b)Write down the equation for hydrostatic equilibrium, including explicitly the variation T(z).

Homework Equations


We can estimate the adiabatic lapse rate with the approximation:
\frac{dT}{dz}|_{ad}=-\frac{g}{c_p}

The equation for hydrostatic equilibrium:
\Delta P = -\rho \Delta z g

The Attempt at a Solution


Part (a) asks me to confirm the adiabatic lapse rate for Venus, which is simple by plugging in g and cp.

Part (b) (asking for the hydrostatic equilibrium equation) is what is confusing me. I am specifically having trouble including T(z). I can find an expression for T(z) by integrating the adiabatic lapse rate approximation:

∫\frac{dT}{dz} dz|_{ad}=∫-\frac{g}{c_p} dz

T(z)=T_0-\frac{g}{c_p}z

I called the constant of integration T0 because that makes sense conceptually.

Now, what I tried was just solving T(z) for g and plugging it into the hydrostatic equilibrium equation because I'm just trying to find a way to include it, but that just yields

\Delta P=-\rho \Delta z \frac{c_p}{z}(T_0-T(z))

which seems useless to me, because T(z) would quickly reduce out with a tiny bit of simplification.

Maybe someone can help by telling me if what I've done so far makes sense and if I should continue, or if I'm just missing something that would make it more clear. Thanks in advance!
 
Last edited:
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ndgoodburn said:
\frac{dT}{dz}|_{ad}=-\frac{g}{c_p}

The equation for hydrostatic equilibrium:
\Delta P = -\rho \Delta z g
Just guessing here, but if \frac{dT}{dz}|_{ad}=-\frac{g}{c_p} then can you not write \Delta T = -\frac{g\Delta z}{c_p} = \frac{g\Delta P}{c_p\rho}?
 

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