The ionization energy of atomic hydrogen?

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SUMMARY

The ionization energy of atomic hydrogen, according to the Bohr theory, is calculated to be 1.31 x 103 kJ/mol. This value is derived using the Bohr equation, E = (-2.18 x 10-18 J)(1/n2), and can also be connected to the Rydberg formula. The variable 'n' represents the principal quantum number, which is 1 for an unexcited hydrogen atom and approaches infinity as the atom becomes ionized, resulting in a significant energy difference.

PREREQUISITES
  • Understanding of the Bohr model of the atom
  • Familiarity with the Rydberg formula
  • Basic knowledge of quantum mechanics and energy levels
  • Ability to perform unit conversions between joules and kJ/mol
NEXT STEPS
  • Study the derivation of the Rydberg formula for hydrogen
  • Learn about the implications of quantum numbers in atomic structure
  • Explore energy level transitions in hydrogen and their spectral lines
  • Investigate the differences between ionization energies of various elements
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Students studying quantum mechanics, chemistry enthusiasts, and educators looking to understand atomic structure and ionization energy calculations.

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Homework Statement


According to the Bohr theory, what is the ionization energy of atomic hydrogen in kJ/mol?

Homework Equations


Bohr equation: E = (-2.18 x 10-18 J)(1/n2)

The Attempt at a Solution


I don't have any general idea on how to do this problem :( please help!

The answer is: 1.31 x 103 kJ/mol
 
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You need to use Rydberg formula. Note, that it can be easily derived from what you called Bohr equation.

Alternatively - what n means? What value does it have in unexcited hydrogen atom? What values does it take when atom gets ionized? These two n values give you two energies - that of unexcited and that of ionized atom. What is the difference between them?

But it boils to exactly the same.
 

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