The length element in cylindrical coordinates

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In cylindrical coordinates, the length element ds is expressed as ds² = dρ² + ρ² dθ² + dz², derived from the relationships x = ρ cos θ, y = ρ sin θ, and z = z. The discussion emphasizes the need to apply the chain rule and total derivatives to find ds², starting with the expressions for the partial derivatives of x and y with respect to ρ and θ. The participant has identified the necessary partial derivatives but is uncertain about how to proceed with the calculations. Clarification on the application of these derivatives is sought to complete the derivation. Understanding these concepts is crucial for successfully demonstrating the length element in cylindrical coordinates.
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Homework Statement



Show that in cylindrical coordinates

x = \rho cos \theta
y = \rho sin \theta
z = z

the length element ds is given by

ds^{2} = dx^{2} + dy^{2} + dz^{2} = d \rho^{2} + \rho^{2} d \theta ^{2} + dz^{2}

Homework Equations



--

The Attempt at a Solution



Notice \rho = \sqrt{x^{2} + y^{2}}

I have found expressions for ∂x/∂θ, ∂x/∂ρ, ∂y/∂θ, ∂y/∂ρ, ∂ρ/∂x, ∂ρ/∂y, ∂θ/∂x, ∂θ/∂y, and of course it is trivial that dz = dz. Given all of these, how do i start using chain rule and total derivatives to find ds2? I guess because i have 8 partials but end up only ρ, θ, and z, i don't really know which ones to start with.

Any help is greatly appreciated.
 
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stripes said:

Homework Statement



Show that in cylindrical coordinates

x = \rho cos \theta
y = \rho sin \theta
z = z

the length element ds is given by

ds^{2} = dx^{2} + dy^{2} + dz^{2} = d \rho^{2} + \rho^{2} d \theta ^{2} + dz^{2}

Homework Equations



--

The Attempt at a Solution



Notice \rho = \sqrt{x^{2} + y^{2}}

I have found expressions for ∂x/∂θ, ∂x/∂ρ, ∂y/∂θ, ∂y/∂ρ, ∂ρ/∂x, ∂ρ/∂y, ∂θ/∂x, ∂θ/∂y, and of course it is trivial that dz = dz. Given all of these, how do i start using chain rule and total derivatives to find ds2? I guess because i have 8 partials but end up only ρ, θ, and z, i don't really know which ones to start with.

Any help is greatly appreciated.

Start from
<br /> dx = \frac{\partial x}{\partial \rho}d\rho + \frac{\partial x}{\partial \theta}d\theta<br />
Squaring both sides gives dx^2.
 
yeah i got it. thanks.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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