I try to figure it out but I can't get the answer that I need and when I look upon the solution from the book I don't understand it at all. The answer is " no limit" and there is no explanation why. The question is(adsbygoogle = window.adsbygoogle || []).push({});

Determine the limit of

lim_{(x2+y2)}_{- -> infinity}(xye^{-(x+y)2}

in this case I use polar coordinate which I get

lim_{r2}_{- -> infinity}( r^{2}cos(x)sin(X) / e^{r^2(1+sin(2x)})

My idea is since there is (e^{r^2(1+sin(2x))}in denominator which is depening on angle (2x) but I am not sure if I understand correct. Can anyone here help me to figure it out? Thanks in advance.

Regard

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# The limit of xye^-(x+y)^2 when x^2+y^2 approach infinity

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