- #1
themountain
- 5
- 1
- Homework Statement
- A .76 meter long wire runs horizontally and carries a current of 28 A from left to right. What would be the magnitude and direction of the minimum magnetic field to suspend the wire in mid air if the wire has a mass of 46.6 g/m
- Relevant Equations
- F=ILB
F=ILB
F=(48)(.76)B
F/36.48=B
I am stuck at how to find F, is there a different formula I am missing?
F=(48)(.76)B
F/36.48=B
I am stuck at how to find F, is there a different formula I am missing?