The magnitudes of the applied force F and the frictional force f of a wheel

  • #1
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Homework Statement
A solid wheel with mass M, radius R, and rotational inertia MR^2/2, rolls without sliding on a horizontial surface. A horizontal force F is applied to the axle and the center of mass has an acceleration a. The magnitudes of the applied force F and the frictional force f of the surface, respectively, are:

a. F = Ma, f = 0
b. F = Ma, f = Ma/2
c. F = 2Ma, f = Ma
d. F = 2Ma, f = Ma/2
e. F = 3Ma/2, f = Ma/2

Ans: E
Relevant Equations
F R = (1/2 MR^2 + MR^2 ) a/R
I calculate in this way as follows and get a correct answer. Howere I am not sure if I am using the right way.

F R = (½ MR^2 + MR^2 ) a/R
F = 3/2 Ma
F - f = Ma
f = 3/2 Ma - Ma = Ma/2
 
  • #2
Homework Statement:: A solid wheel with mass M, radius R, and rotational inertia MR^2/2, rolls without sliding on a horizontial surface. A horizontal force F is applied to the axle and the center of mass has an acceleration a. The magnitudes of the applied force F and the frictional force f of the surface, respectively, are:

a. F = Ma, f = 0
b. F = Ma, f = Ma/2
c. F = 2Ma, f = Ma
d. F = 2Ma, f = Ma/2
e. F = 3Ma/2, f = Ma/2

Ans: E
Relevant Equations:: F R = (1/2 MR^2 + MR^2 ) a/R

I calculate in this way as follows and get a correct answer. Howere I am not sure if I am using the right way.

F R = (½ MR^2 + MR^2 ) a/R
F = 3/2 Ma
F - f = Ma
f = 3/2 Ma - Ma = Ma/2
The safest way with angular acceleration is to take moments about either the mass centre or a fixed point.
You have effectively taken the second option.
 
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Likes Delta2 and hidemi
  • #3
The safest way with angular acceleration is to take moments about either the mass centre or a fixed point.
You have effectively taken the second option.
Thanks for commenting.
 

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