The molar heat of combustion for phenol

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SUMMARY

The molar heat of combustion for phenol was calculated using a calorimeter with a heat capacity of 1,483 J K-1 and a temperature rise of 1.83 °C. The calculation involved determining the number of moles of phenol burned, which was found to be 1.09859E-3 mol. The final result for the molar heat of combustion was calculated as 371,198.84 kJ/mol. The discussion emphasized the importance of correctly applying the temperature change in the calculations.

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  • Basic thermodynamics, specifically enthalpy changes
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You burn 103.4 mg of phenol in a calorimeter of heat capacity 1,483 J K-1 and the temperature rises by 1.83 oC. Determine the molar heat of combustion for phenol in kJ mol-1. The molar mass of phenol is 94.12 g mol-1

Ccal=deltaH/ deltaT

This is what I did.
n=.1034/94.12
=1.09859E-3mol

deltaH=(1483J/K*274.98K)/1.09859E-3
deltaH=371198.84kJ/mol

What did I do wrong... any help would be appreciated. thanks!
 
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Your equation calls for deltaT, so that means the change in temperature.

You were given deltaT in the question. Remember that 1 degree celsius = 1 degree Kelvin, so the difference of two temperatures will be the same on either scale.
 
Hey Thanks... that's helpful... I got the answer to the answer right thanks a heap!
 

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