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**The net force on a moving positive charge....**

## Homework Statement

A magnetic field has a magnitude of 1.2 x10^-3 T, and an electric field has a magnitude of 5.4 x10^3 N/C. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 2.9x10^6 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.

## Homework Equations

Force = qE

Force = qvBsin(theta)

Electric force + Magnetic force = Net force

## The Attempt at a Solution

qE + qvBsin(theta) = net force

(1.8e-6 C * 5.4e^3 N/C ) + ( 1.8e-6C * 2.9e^6m/s *1.2e^-3T*sin(90) =

.0972N + .006264N = .1035N of net force

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