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Dart82
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The net force on a moving positive charge...
A magnetic field has a magnitude of 1.2 x10^-3 T, and an electric field has a magnitude of 5.4 x10^3 N/C. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 2.9x10^6 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.
Force = qE
Force = qvBsin(theta)
Electric force + Magnetic force = Net force
qE + qvBsin(theta) = net force
(1.8e-6 C * 5.4e^3 N/C ) + ( 1.8e-6C * 2.9e^6m/s *1.2e^-3T*sin(90) =
.0972N + .006264N = .1035N of net force
Homework Statement
A magnetic field has a magnitude of 1.2 x10^-3 T, and an electric field has a magnitude of 5.4 x10^3 N/C. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 2.9x10^6 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.
Homework Equations
Force = qE
Force = qvBsin(theta)
Electric force + Magnetic force = Net force
The Attempt at a Solution
qE + qvBsin(theta) = net force
(1.8e-6 C * 5.4e^3 N/C ) + ( 1.8e-6C * 2.9e^6m/s *1.2e^-3T*sin(90) =
.0972N + .006264N = .1035N of net force
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