The number of times the function vanishes

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Homework Help Overview

The discussion revolves around determining the number of times the function \(\sum_1^{2009} \dfrac{r}{x-r}\) vanishes. Participants are exploring the implications of the function's structure and behavior near its critical points.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss expanding the sum and analyzing the resulting polynomial's roots. Questions arise regarding the nature of these roots, particularly their reality and uniqueness. Some suggest examining the behavior of the function as \(x\) approaches integer values to understand root existence.

Discussion Status

The discussion is active, with various lines of reasoning being explored. Participants are considering the implications of the Intermediate Value Theorem and the behavior of the function near integers. There is no explicit consensus yet, but several productive avenues are being investigated.

Contextual Notes

Participants are working under the constraints of the problem's setup, particularly regarding the behavior of the function in different ranges of \(x\) and the implications of the sum's terms.

utkarshakash
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Homework Statement


The number of times the function \sum_1^{2009} \dfrac{r}{x-r} vanishes is

Homework Equations



The Attempt at a Solution


Expanding the sum and writing first few terms of it

\frac{1}{x-1} + \frac{2}{x-2} + \frac{3}{x-3} ...

Now if I take the LCM I will get a polynomial of degree 2008 in the numerator and (x-1)(x-2)...(x-2009) in the denominator. f(x) vanishes when the num becomes 0. In other words I have to find roots of the num. But how can I be sure that all its 2008 roots will be real?
 
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You might want to consider what happens when x is very close to an integer, and what that implies about the existence of roots.
 
The Intermediate Value Theorem could be useful.
 
Office_Shredder said:
You might want to consider what happens when x is very close to an integer, and what that implies about the existence of roots.

When x is very close to an integer lying between 1 and 2009 denominator tends to zero and f(x) tends to infinity. How does this help me?
 
No, it doesn't always tend to infinity, sometimes it tends to something else... Think about the graph of 1/x
 
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If x < 1 this sum consists entirely of negative terms, so will have not zeros in that range. Suppose n < x < n+1. Then all the terms up to n/(x-n) will be positive and all the rest will be negative. It seems that there may be an x where the positive and negative terms cancel.

If there is such an x, it must be the only one, because making it larger will make create more positive terms and fewer negative terms, and making it smaller vice versa. Can you formalize a way to say this?

Could it be that there is no such x? Why or why not?
 

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