The period of summation functions

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Homework Help Overview

The discussion revolves around finding the period of summation functions, specifically involving terms like 2^-k and cos(pi k) multiplied by complex exponentials such as ei7kt. The original poster is exploring how to determine the period of these summations in the context of Fourier analysis.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find the period of a summation function and questions whether omega is 7k based on Euler's method. They also inquire about the formula for finding the period of summations of complex exponentials.

Discussion Status

Participants are engaging in a back-and-forth regarding the definition of periodicity and whether the original poster's reasoning aligns with it. Some guidance has been offered regarding the definition, but there is uncertainty as the original poster's friend has suggested a potential error in their reasoning.

Contextual Notes

There is mention of a friend's disagreement with the original poster's understanding, indicating a possible divergence in interpretations or assumptions about the periodicity of the function in question.

Luongo
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1. how do i find the period of summation of some function ie: 2^-k or cos(pi k) multiplied by some complex exponential ei7kt

ie: f( t ) = \sum
2-kei7kt
2. does anyone know the formula for finding the period of summations of complex exponentials? note this is for fourier
3. would i say that omega is 7k by Euler's method. if i converted to sines and cosines, thus the period T = 2pi/7?
is this how i would find the period of this summation?
 
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The definition of periodicity is as follows:
If T is the period of a function f(t) then,
f(t+ T) = f(t).

Does your answer admit to this definition ?
 
╔(σ_σ)╝ said:
The definition of periodicity is as follows:
If T is the period of a function f(t) then,
f(t+ T) = f(t).

Does your answer admit to this definition ?

i think so thanks
 
You are welcome. :-)
 
╔(σ_σ)╝ said:
You are welcome. :-)


my friend said i am wrong...?
 
Luongo said:
my friend said i am wrong...?
What is his reasoning ?
 

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