The position of the object is on the place of the question mark.

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Homework Help Overview

The discussion revolves around a problem involving a convex mirror with a focal length of 10 cm, where the image formed is one quarter the size of the object. Participants are trying to determine the positions of both the object and the image using the mirror formula and magnification concepts.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the mirror equation and magnification formula, with one participant attempting to solve for the object distance (u) and image distance (v). There are questions about handling fractions and finding common denominators in the equations.

Discussion Status

The discussion is ongoing, with some participants providing hints and corrections regarding the signs in the equations. There is an acknowledgment of the mathematical challenges faced, particularly in combining fractions. Multiple interpretations of the problem setup are being explored.

Contextual Notes

Participants are navigating the constraints of the problem, including the specific characteristics of convex mirrors and the implications of the magnification ratio. There is also a mention of the original poster's awareness of a potential solution, which adds to the complexity of the discussion.

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Homework Statement


A convex mirror of focal length 10cm forms an image that is one quarter the size of the object. Find the position of the object and the image.

Homework Equations


-1/f = 1/u + 1/v
m = v/u

The Attempt at a Solution


m = 1/4
f = 10cm
-1/10 = 1/u + 1/0.25u

I think that 1/u + 0.25u is the problem because I can't find the common denominator. The answer to the question is u = 30cm, v = 7.5cm just in case someone thinks I want them to do my homework for me. I just want to understand how to get it. Thanks.
 
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Dude, relax. Getting impatient after just one hour is not going to help you.
By the way, how does telling us that you know the answer prove anything?

Anyway, your last equation looks correct, except that you need to be careful with the sign of v... the mirror is convex, so it's like a negative lens: it will produce an image on the same side as the object. Hence, v = -0.25u.

Correcting that, you just have a problem with your math. Because in principle,
-1/10 = 1/u - 1/0.25u
is a single equation in one unknown (u), so you can easily solve for u.

Hint: multiply through by u.
 
I still don't understand. The point I'm trying to make is that I don't know how to get the common denominator when there's a fraction and a number. I just need someone to tell me how.
 
OK, you can also combine the two fractions by making a common denominator...

Then can you answer me this: what should be on the place of the question mark in
[tex]\frac{1}{u} = \frac{?}{0.25 \cdot u}[/tex]
 

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