The ratio between two horizontal speeds in this pendulum arrangement

Thread starter billtodd
Start date Mar 27, 2024
Tags

equations Horizontal Torque

AI Thread Summary

The discussion focuses on deriving the torque equations for a pendulum system based on the forces acting on it. The user understands the normal force and tension equations but struggles with formulating the torque equations. Another participant requests clarification on the setup and asks for the text from an attachment to better assist. The conversation highlights the need for clear communication of the pendulum's configuration to facilitate problem-solving. Overall, the thread emphasizes the importance of understanding both forces and torques in analyzing pendulum dynamics.

Mar 27, 2024

billtodd

Homework Statement: To find the ratio between the horizontal speed of the stick with mass ##M## and the small point with mass ##m##.

Relevant Equations: Force equation and torque.

From the forces equation I can only understand from it that the forces' equations are:##N=Mg## and ##T\sin \theta=m\ell \ddot{\theta}##.

But I don't know how to find the Torques' equations.

Any help is appreciated.

N=Mg ##Tcos⁡θ+N=mg

Physics news on Phys.org

Mar 27, 2024

berkeman

Admin

Could you please type out the text from your attachment, and explain that setup? Thanks.

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »

Thread 'Minimum mass of a block'

Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...

View full post »