The ratio between two horizontal speeds in this pendulum arrangement

Thread starter billtodd
Start date Mar 27, 2024
Tags

equations Horizontal Torque

Click For Summary

SUMMARY

The discussion focuses on deriving the torque equations for a pendulum arrangement, specifically analyzing the forces involved. The key equations mentioned are N=Mg and Tsin(θ)=mℓ¨θ, which relate to the normal force and tension in the pendulum system. Participants seek clarification on how to formulate the torque equations based on these forces. The conversation emphasizes the need for a deeper understanding of torque in relation to angular motion.

PREREQUISITES

Understanding of basic physics concepts such as forces and torques.
Familiarity with pendulum mechanics and angular motion.
Knowledge of trigonometric functions as they apply to physics.
Ability to interpret and manipulate equations involving tension and normal forces.

NEXT STEPS

Research the derivation of torque equations in pendulum systems.
Study the relationship between angular acceleration and tension in pendulums.
Explore the application of Newton's second law in rotational dynamics.
Learn about the role of trigonometric functions in analyzing forces in pendulum motion.

USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of pendulum systems will benefit from this discussion.

Mar 27, 2024

billtodd

Homework Statement: To find the ratio between the horizontal speed of the stick with mass ##M## and the small point with mass ##m##.

Relevant Equations: Force equation and torque.

From the forces equation I can only understand from it that the forces' equations are:##N=Mg## and ##T\sin \theta=m\ell \ddot{\theta}##.

But I don't know how to find the Torques' equations.

Any help is appreciated.

N=Mg ##Tcos⁡θ+N=mg