The total quantity of heat received by the soup

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In summary, the soup of mass 0.40kg, initially at -15°C, is heated in a microwave for 6 minutes until it reaches a temperature of 75°C. The specific heat capacity of the soup in its solid state is 2100J/kg°C, while in its liquid state it is 4200J/kg°C. The latent heat of fusion for the soup is 330000J/kg and its melting point is 0°C. The total quantity of heat received by the soup is 270600J.
  • #1
mms0101
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Homework Statement


frozen soup of a mass of 0,40kg enters a microwave at -15°C. after 6 minutes the soup eaches a ° of 75°C
SHC of soup at solid state : c = 2100J/kg°C
SHC of liquid soup : c = 4200K/kg°C
SLH of fusion of soup : Lf = 330 000J/kg
melting point of soup : 0°C
THE QUESTION : WHAT IS THE TOTAL QUANTITY OF HEAT RECEIVED BY THE SOUP ?

Homework Equations


E = mcΔt
E= mL

The Attempt at a Solution


E = mcΔT
= 0,4 x 2100 x 15
=12600 J

E = mL
= 0,4 x 330 000
=132000J

E = mcΔT
= 0,4 x 4200 x 75
=126000

Etot = 132,000 + 12600 + 126000
=270600 J

teachers answer : 2 671 000 J
i have no idea how to get to it i am in my 5th year at the european school

Homework Statement


Homework Equations


The Attempt at a Solution

 
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  • #2
mms0101,

I can't see anything wrong with your answer.

Ratch
 
  • #3
You're right, teach is wrong. Sure that was his answer?
 
  • #4
ill go talk to him tomorrow as i have another answer to do with circuits that mismatch his ill let you know :) thank you anyway
 
  • #5
Based on the given information, the total quantity of heat received by the soup can be calculated by adding the heat required for the soup to reach its melting point, the heat required for the soup to melt, and the heat required for the soup to reach its final temperature. This can be expressed as:

Etot = E1 + E2 + E3

Where:
E1 = Heat required for the soup to reach its melting point
E2 = Heat required for the soup to melt
E3 = Heat required for the soup to reach its final temperature

To calculate E1, we can use the specific heat capacity of the soup in its solid state:

E1 = mcΔT
= 0.4 kg x 2100 J/kg°C x (0°C - (-15°C))
= 12600 J

To calculate E2, we can use the specific latent heat of fusion of the soup:

E2 = mL
= 0.4 kg x 330000 J/kg
= 132000 J

To calculate E3, we can use the specific heat capacity of the soup in its liquid state:

E3 = mcΔT
= 0.4 kg x 4200 J/kg°C x (75°C - 0°C)
= 126000 J

Therefore, the total quantity of heat received by the soup is:

Etot = 12600 J + 132000 J + 126000 J
= 270600 J

It is possible that the teacher's answer of 2,671,000 J is a mistake, as it is significantly higher than the calculated value. It is important to double check the calculations and units used to ensure accuracy.
 

1. What is the meaning of "total quantity of heat received by the soup"?

The total quantity of heat received by the soup refers to the amount of thermal energy that is absorbed by the soup from its surroundings.

2. How is the total quantity of heat received by the soup measured?

The total quantity of heat received by the soup can be measured using a thermometer to determine the change in temperature from its initial state to its final state.

3. What factors affect the total quantity of heat received by the soup?

The total quantity of heat received by the soup can be affected by various factors such as the initial temperature of the soup, the temperature of its surroundings, and the type of container the soup is in.

4. Why is it important to consider the total quantity of heat received by the soup?

Knowing the total quantity of heat received by the soup is important because it can affect the overall flavor and quality of the soup. It can also help determine the appropriate heating or cooling time for the soup.

5. How can the total quantity of heat received by the soup be controlled?

The total quantity of heat received by the soup can be controlled by adjusting the temperature of its surroundings, using a different type of container, or stirring the soup to evenly distribute the heat.

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