In CE amplifiers with negative feedback I can't understand what it means that the emitter becomes more positive (when hfe increases and VE increases with it). Does it mean that there is less negative charge after the emitter resistor (going from ground to Vcc) and the emitter feels some positive charge and the potential difference between the emitter and the base is decreased or what? Physicaly I can't explain it. Not theoreticaly, but physicaly. Help me with this one if you can EDIT#1 I understand that electrons in the - terminal of the battery, in order to flow through the circuit, they must be given the needed potential energy. This potential energy - the energy density of a charge J/C is the thing the electrons need so that they can actualy start a current. By flowing from ground to the high potential, the electrons inevitably encounter resistance and they lose this energy to heat. And when they arrive at Vcc they have already spend all of the potential energy given to them to fulfill this "journey". But how can I imagine the rising emitter voltage VE duo to negative feedback?