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The "x'=x-vt" in Galilean/Lorentz transformation

  1. Mar 26, 2015 #1
    Hello people,
    I have a question regarding the x' component in the Lorentz/Galilean transformation.
    So from what i understand is that there are 2 coordinate systems used in the transformations. One is used as a reference point and one is used for moving away from this point. The moving away in x-axis is described with x'=x-vt but where does the "-vt" come from and why is it "minus vt" and not "positive vt"?

    Is the sign determined by how the prime(')-coordinate system moves relative to the other system? (So it's -vt when you move against the direction of the x-axis?)
     
  2. jcsd
  3. Mar 26, 2015 #2

    Mentz114

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    Gold Member

    You can work out the direction of motion by checking if x' increases or decreases with t.
     
  4. Mar 26, 2015 #3

    Ibix

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    You can draw a displacement-time graph for a pair of objects moving at speed v. What is the equation of the line in terms of x and t? Can you relate x' to this? Drawing an x' vs t graph may help with the latter.
     
  5. Mar 27, 2015 #4
    It's geometric. The S' frame is moving with positive velocity v relative to the S frame. Draw a picture showing the location of the S' frame relative to the S frame at two different times, and you will see visually how this plays out.

    Chet
     
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