Nabeshin said:
You think I'm accidentally mixing equations from two different reference frames in my work equation?
Yes, and I guess I am also a bit puzzled about what energy it really makes sense to analyse. I assume that since the paper strives to establish limits and constraints to "practical" relativistic flight the energy used must be something that would be relevant for the design of a propulsive system for such flights.
I can only see to options (or extreme end-points, if you will) for the propulsive system: either the mass of the vehicle is unchanged by propulsion and all change in vehicle momentum and energy comes from the Earth frame, or the vehicle is a self-contained rocket delivering its "own" change in momentum and energy with no particular tie to the Earth frame once the trip has started. In the first case I gather it makes sense to analyse the power transferred to the vehicle, like if we consider the vehicle as a big particle in a linear relativistic accelerator. In the second case it seems to make more sense to analyse the engine energy (or jet power) required in the rocket frame since this is where all the action takes place.
Here was my thought process in deriving it:
Start with the most basic, everyone knows that
W=\int F dx
So initially the Earth will observe an acceleration a0, which by Newton's good ol' 2nd is a force of ma0. Seeing as we run the engine at the same capacity throughout the entire voyage, I call this force a constant and remove it from the integral.
W=ma_0 \int dx
Are we in agreement up until this point? Or do you disagree with this argument so far? I'll assume we're okay...
I'm not sure what frame you are using here.
If you select the Earth frame, then the acceleration is decreasing with a factor 1/\gamma^3 and (relativistic) mass is increasing with a factor \gamma, so force is overall decreasing with factor 1/\gamma^2 and can hardly be considered constant except for short trip, right? And if you do want to evaluate this integral in the Earth frame, wouldn't it then make more sense to use relativistic energy-momentum equation like for a particle accelerated to relativistic speeds in a lab?
Alternatively, if you select to integrate in the rocket frame but use the contracted path length "back" to Earth as distance, then I'm puzzled if this Newtonian integral is a "legal" integral for work in a relativistic context. I mean, the path is obviously being contracted which means that if the propulsive system delivers more energy (e.g. operates for a longer time) it will have done its work over a shorter path and therefore delivered less energy? (Edit: there is a bit too much hand-waving in that last conclusion - please just read this as an indication that I am confused) That does not make sense to me, so either I missed something or the integral is "dubious". It may be that there are some "trick" where you perhaps can transform a Newtonian work integral from the rocket frame to the Earth frame using hyperbolic trigonometry (like Newtonian speeds that are added algebraically can be transformed using hyperbolic tangent), but it seem you then ought to arrive with something similar to the energy-momentum equation if conservation of energy and momentum still are to hold.
Finally, if you select to integrate in the rocket frame, but use the uncontracted "Newtonian" path length the rocket itself "sees", then we are back at a work integral that looks valid, but which are then expressing the energy required solely from the vehicles frame, i.e. its the jet power. Using the specific jet power (like equation (3)) has the benefit that its value seems to be constant and equal both for constant mass vehicles getting propulsion energy from the Earth frame and for self-contained rockets, thus charactering the lower bound of energy usage not matter the design of the propulsive system.
So, as you can probably gather, I have talked myself pretty warm on giving the last option the most sense, ie. that the energy considered are the integral of the jet power.
Now the question is, which path length is this: the one observed from the Earth or the one observed from the ship's point of view? Owing to length contraction, the ship necessarily traverses a shorter path than the 4.2 ly, so the two numbers do not coincide. I think this is where your disagreement actually lays, no? In the paper, the original version had just the Earth distance, but I dropped this in favor of the ship distance in about September. Now that you got me thinking about it again, I'm not entirely sure...
We can imagine some giant hand from the Earth physically pushing the ship along its voyage. No doubt the hand pushes through the full distance d. But is the force it pushes with always necessarily ma0?
According to my argument earlier I would say no. As seen from the Earth frame the force cannot in general be constant if the local acceleration of the rocket is constant.
I think a (somewhat) simpler example might be the following: The spacecraft consumes power at a rate P, for simplicity, say 1MW. Say they go on a quick trip. Earth says it took you 100 days to complete the trip, you must have used 100days*1MW of power. The ship says no, it took us 10 days and we used 10days*1MW of power. I think in this circumstance my intuition is much stronger to suggest that the ship's bookkeeping is the correct one. By analogy, then, the formula given in the paper should be correct.
While I do agree that the rocket frame is the "interesting" frame here, I also think the problem with this particular argument is that its assumptions do not hold. If you select the Earth frame the power will decrease over time, and I would in fact boldly claim, that if we invoke the principle of conservation of energy, then all types of work integrals should end up giving the same value for the whole system (e.g. possibly including any ejected fuel). So, selection of frame or path really should not affect the final value of the energy, only the ease of which the integral may be calculated with.
What do you think, or have I completely missed your argument?
Not completely missed, no, but it is not right on target either as I have tried to argument for above
If you are interested in resolving this issue, then perhaps you can make some numerical experiments and test the various ways to calculate energy for short and long trips. While a trip for, say, one million light years are pure engineering science fiction, it may provide a hint to which energy values that are sensible considering the vehicle only travels for a short time.